Pinnacle P1

[TtTOtW]

Try using two rocket, one at each end, and see how many tons it can withstand

Good idea.

 

[TheSpacePioneer]

Ok that was from LEO. Let's try in excess of 22000km. Surely 10+g will pull it apart. I was really really curious...
View attachment 12958
View attachment 12957 View attachment 12956 View attachment 12955 View attachment 12954 View attachment 12953 View attachment 12952 View attachment 12951 View attachment 12950 View attachment 12949
... and nothing. Solid as a rock. This thing was dropping speed at over 100m/s per second at one point. But not a sign of movement.

jeeze

 

[TheSpacePioneer]

I got an idea. Maybe you could cover the whole thing in solar panels? They seem to be indestructable. XD

 

[TtTOtW]

nearly.

 

[Zeeray13]

I am glad I started at 1.3. Opens your mind.

I started when this game first came out on andriod there was only 1 fuel tank 1 capsule landing legs 2 types of parachutes 2 engines and that was really it no fancy rcs or even cunstruction blocks not even the 4×8 tank was in the game

 

[Danny Batten]

I started when this game first came out on andriod there was only 1 fuel tank 1 capsule landing legs 2 types of parachutes 2 engines and that was really it no fancy rcs or even cunstruction blocks not even the 4×8 tank was in the game

It was simple back then, fun but simple

 

[Zeeray13]

It was simple back then, fun but simple

I remember when i had to fill the entire build so i could get to just the moon

 

[InSight]

The formula is:
delta-V = g×ISP×Ln(1+fuel_mass/dry_mass)

If you prefer, there are several calculators that allow to calculate easily all that sort of stuff.
For example, if you take that single stage:
View attachment 12948
Its delta-V at full capacity is 2835 m/s. For such a light ship it's not really useful to try to save a few tens of m/s.
Especially that if your slingshot maneuver isn't really precise, you could even spend more delta-V than for a direct transfer
That's why I don't recommend using the Moon for this, this really complicates things for practically no benefit.

Is there ln(1+f/d)?

I thought it is 9.8*isp*ln(full mass/dry mass)

 

[Altaïr]

Is there ln(1+f/d)?

I thought it is 9.8*isp*ln(full mass/dry mass)

That one is correct too, but my "f" is for "fuel", not "full". I tend to prefer that form, but your formula is the most usual one indeed. Sorry for the confusion.